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2x^2-41x-180=0
a = 2; b = -41; c = -180;
Δ = b2-4ac
Δ = -412-4·2·(-180)
Δ = 3121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-\sqrt{3121}}{2*2}=\frac{41-\sqrt{3121}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+\sqrt{3121}}{2*2}=\frac{41+\sqrt{3121}}{4} $
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